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	<title>Comments on: 耐人尋味找奇數</title>
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		<title>By: marky</title>
		<link>http://jacky.seezone.net/2005/03/22/1169/comment-page-1/#comment-1257</link>
		<dc:creator>marky</dc:creator>
		<pubDate>Wed, 23 Mar 2005 20:41:46 +0000</pubDate>
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		<description>好醒丫...:D</description>
		<content:encoded><![CDATA[<p>好醒丫...:D</p>
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		<title>By: Gea-Suan Lin's BLOG</title>
		<link>http://jacky.seezone.net/2005/03/22/1169/comment-page-1/#comment-1258</link>
		<dc:creator>Gea-Suan Lin's BLOG</dc:creator>
		<pubDate>Tue, 22 Mar 2005 17:02:12 +0000</pubDate>
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		<description>&lt;strong&gt;奇數&lt;/strong&gt;

在「耐人尋味找奇數」裡面提到的方法其實還算好，O(1) :p

我記得之前有看到類似的文章，也是判斷奇數的，下面是其中一種方法 :p
int isOdd(int n)
{
	if (n &lt; 2)
		return (n != 0);
	else
		return (...
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		<content:encoded><![CDATA[<p><strong>奇數</strong></p>
<p>在「耐人尋味找奇數」裡面提到的方法其實還算好，O(1) :p</p>
<p>我記得之前有看到類似的文章，也是判斷奇數的，下面是其中一種方法 :p<br />
int isOdd(int n)<br />
{<br />
	if (n &lt; 2)<br />
		return (n != 0);<br />
	else<br />
		return (...</p>
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